DECLARE @a TABLE(A int IDENTITY(1,1) PRIMARY KEY, B int, C int, D int);


INSERT INTO @a (B, C, D) VALUES (100, 30, 1)
INSERT INTO @a (B, C, D) VALUES (100, 30, 2)
INSERT INTO @a (B, C, D) VALUES (100, 30, 3)
INSERT INTO @a (B, C, D) VALUES (100, 40, 4)
INSERT INTO @a (B, C, D) VALUES (100, 40, 5)
INSERT INTO @a (B, C, D) VALUES (200, 30, 1)
INSERT INTO @a (B, C, D) VALUES (200, 30, 2)
INSERT INTO @a (B, C, D) VALUES (200, 30, 3)
INSERT INTO @a (B, C, D) VALUES (200, 40, 4)
INSERT INTO @a (B, C, D) VALUES (200, 40, 5)
INSERT INTO @a (B, C, D) VALUES (300, 30, 1)
INSERT INTO @a (B, C, D) VALUES (300, 30, 2)
INSERT INTO @a (B, C, D) VALUES (300, 40, 3)
INSERT INTO @a (B, C, D) VALUES (400, 40, 4)
INSERT INTO @a (B, C, D) VALUES (400, 40, 5)
INSERT INTO @a (B, C, D) VALUES (500, 30, 1)
INSERT INTO @a (B, C, D) VALUES (500, 30, 2)
INSERT INTO @a (B, C, D) VALUES (500, 30, 3)
INSERT INTO @a (B, C, D) VALUES (500, 40, 4)
INSERT INTO @a (B, C, D) VALUES (500, 40, 5)
INSERT INTO @a (B, C, D) VALUES (500, 31, 6)

--SELECT * FROM @a

DECLARE @i INT ;
SET @i = 200 ;

-- solution

The above solutions return 500 even though it contains _6_ records and
200 contains 5 records.