Miguel Angel Tribaldos Hervas <mitriher@teleco.upv.es> writes:
> I am working with inheritance in postgresql 7.4. If I create a table named A,
> and another named B that inherits from A, if I perform a query such a
> "SELECT * FROM A" (without ONLY clause),
> how can I get the type (identifier from pg_type) of the returned records??

I think what you are after is the "tableoid" system column. Try
SELECT tableoid, * FROM A;
or more readably
SELECT tableoid::regclass, * FROM A;
or you can do the above "by hand"
SELECT p.relname, A.* FROM A, pg_class p WHERE p.oid = a.tableoid;

If you really want the composite type IDs then it's
SELECT p.reltype, A.* FROM A, pg_class p WHERE p.oid = a.tableoid;

regards, tom lane

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