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Old 01-17-2008, 05:49 AM
joel.pavon@intl.fritolay.com
 
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Default Cuestion about process using AWK

Hi, I'm trying to find process to spend more than 100 second of CPU
Resource, I'M ussing the command:

ps -ef | grep http | awk '{if ($8=="http" && $7>="100:00") print $0}'
| sort -n -k 7

But it show

applmgr 143 9484 0 11:47:58 ? 0:34 http webfile=5,2319
applmgr 204 9484 0 08:10:42 ? 0:56 http webfile=5,1829
applmgr 278 9484 0 14:32:53 ? 0:04 http webfile=5,2597
applmgr 649 9484 0 15:14:13 ? 0:09 http webfile=5,2667
applmgr 750 9484 0 13:49:44 ? 0:43 http webfile=5,2550


I need to show only the process who are grater than 100:00 in the
column number 7.

apreciate any help!!

Regards.

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