SEO

permalink · #1 (**permalink**) 01-05-2008, 10:06 AM

Hi everyone,

I'm kinda new to the Unix world, so there may be an obvious answer to
this question but I just haven't been able to find it.

I'm writing a script in perl that will find users in /etc/security/user
that have "account_locked=true" or "login=false".

My question is: is there a function, module, command, anything that
will do this easily; just put the username (and desired attributes) as
an argument and it will bring back results? So I don't have to mess
with a bunch of metacharacters searching through each username's
attributes.

Any help would be appreciated, thank you!

Joe

permalink · #2 (**permalink**) 01-05-2008, 10:07 AM

degeneration32@hotmail.com wrote:
> Hi everyone,
>
> I'm kinda new to the Unix world, so there may be an obvious answer to
> this question but I just haven't been able to find it.
>
> I'm writing a script in perl that will find users in /etc/security/user
> that have "account_locked=true" or "login=false".
>
> My question is: is there a function, module, command, anything that
> will do this easily;

man lssec
man lsuser

just from memory
Hajo

permalink · #3 (**permalink**) 01-05-2008, 10:07 AM

Hajo Ehlers wrote:
> degeneration32@hotmail.com wrote:
> > Hi everyone,
> >
> > I'm kinda new to the Unix world, so there may be an obvious answer to
> > this question but I just haven't been able to find it.
> >
> > I'm writing a script in perl that will find users in /etc/security/user
> > that have "account_locked=true" or "login=false".
> >
> > My question is: is there a function, module, command, anything that
> > will do this easily;
>
> man lssec
> man lsuser
>
> just from memory
> Hajo

Thanks a lot, lssec seems to be what I was looking for.

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Accessing /etc/security/user attributes