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  #1 (permalink)  
Old 02-24-2008, 01:49 PM
dereksmi@gmail.com
 
Posts: n/a
Default non equi-joins



Hi,

I have two tables t1 and t2 containing 10K tuples each. I tried to do a
non equi-join on these tables using the following query.

select /*+ ORDERED USE_MERGE (t2 t1)*/count(*) from test2 t2, test1 t1
where t2.a > t1.a;

A simple implementaion of Sort merge based non equi join would have
sorted both relations and iterated through the outer relation returning
all the matching tuples. However when I checked the execution plan made
by Oracle. this is wot it shows


Rows Row Source Operation
------- ---------------------------------------------------
1 SORT AGGREGATE (cr=76 pr=0 pw=0 time=26809424 us)
49995000 MERGE JOIN (cr=76 pr=0 pw=0 time=150014986 us)
10000 SORT JOIN (cr=38 pr=0 pw=0 time=26064 us)
10000 TABLE ACCESS FULL TEST2 (cr=38 pr=0 pw=0 time=10086 us)
49995000 SORT JOIN (cr=38 pr=0 pw=0 time=50031081 us)
10000 TABLE ACCESS FULL TEST1 (cr=38 pr=0 pw=0 time=10055 us)


Why does it sort the inner relation multiple times? Is there a way to
avoid it? Any help would be greatly appreciated!!

best regards,
Derek.

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  #2 (permalink)  
Old 02-24-2008, 01:49 PM
fitzjarrell@cox.net
 
Posts: n/a
Default Re: non equi-joins



dereksmi@gmail.com wrote:
> Hi,
>
> I have two tables t1 and t2 containing 10K tuples each. I tried to do a
> non equi-join on these tables using the following query.
>
> select /*+ ORDERED USE_MERGE (t2 t1)*/count(*) from test2 t2, test1 t1
> where t2.a > t1.a;
>
> A simple implementaion of Sort merge based non equi join would have
> sorted both relations and iterated through the outer relation returning
> all the matching tuples. However when I checked the execution plan made
> by Oracle. this is wot it shows
>
>
> Rows Row Source Operation
> ------- ---------------------------------------------------
> 1 SORT AGGREGATE (cr=76 pr=0 pw=0 time=26809424 us)
> 49995000 MERGE JOIN (cr=76 pr=0 pw=0 time=150014986 us)
> 10000 SORT JOIN (cr=38 pr=0 pw=0 time=26064 us)
> 10000 TABLE ACCESS FULL TEST2 (cr=38 pr=0 pw=0 time=10086 us)
> 49995000 SORT JOIN (cr=38 pr=0 pw=0 time=50031081 us)
> 10000 TABLE ACCESS FULL TEST1 (cr=38 pr=0 pw=0 time=10055 us)
>
>
> Why does it sort the inner relation multiple times? Is there a way to
> avoid it? Any help would be greatly appreciated!!
>
> best regards,
> Derek.


Why do you post the same message multiple times? Such behaviour does
not bode well for a useful response. Post your question ONCE, and in
properl English, and wait; should someone be able to provide
enlightenment, they will.

I've created and loaded two tables, t1 and t2, with sequential data.
The query plan I generate for your query is:

--------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost |
--------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 26 | 146 |
| 1 | SORT AGGREGATE | | 1 | 26 | |
| 2 | MERGE JOIN | | 5640K| 139M| 146 |
| 3 | SORT JOIN | | 10001 | 126K| 69 |
| 4 | TABLE ACCESS FULL| T1 | 10001 | 126K| 2 |
|* 5 | SORT JOIN | | 11280 | 143K| 77 |
| 6 | TABLE ACCESS FULL| T2 | 11280 | 143K| 2 |
--------------------------------------------------------------------

Additinoal information I obtained:

Predicate Information (identified by operation id):
---------------------------------------------------

5 - access("T2"."A">"T1"."A")
filter("T2"."A">"T1"."A")

Modifying your query to remove the hint and generating another plan
produces:

--------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost |
--------------------------------------------------------------------
| 0 | SELECT STATEMENT | | | | |
| 1 | SORT AGGREGATE | | | | |
| 2 | NESTED LOOPS | | | | |
| 3 | TABLE ACCESS FULL | T2 | | | |
|* 4 | TABLE ACCESS FULL | T1 | | | |
--------------------------------------------------------------------

Your hint, it appears, is causing you grief, as the un-hinted query
performs as you'd expect. Notice, too, no costing information is
present in this plan. dbms_xplan.display reveals this is a rule-based
optimisation.

Generating statistics on these tables and running your query again:

--------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost |
--------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 6 | 98 |
| 1 | SORT AGGREGATE | | 1 | 6 | |
| 2 | MERGE JOIN | | 5000K| 28M| 98 |
| 3 | SORT JOIN | | 10000 | 30000 | 49 |
| 4 | TABLE ACCESS FULL| T1 | 10000 | 30000 | 9 |
|* 5 | SORT JOIN | | 10000 | 30000 | 49 |
| 6 | TABLE ACCESS FULL| T2 | 10000 | 30000 | 9 |
--------------------------------------------------------------------

No real difference except the cost. Generating another plan for the
un-hinted query (this time using the CBO instead of the RBO):

--------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost |
--------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 6 | 98 |
| 1 | SORT AGGREGATE | | 1 | 6 | |
| 2 | MERGE JOIN | | 5000K| 28M| 98 |
| 3 | SORT JOIN | | 10000 | 30000 | 49 |
| 4 | TABLE ACCESS FULL| T1 | 10000 | 30000 | 9 |
|* 5 | SORT JOIN | | 10000 | 30000 | 49 |
| 6 | TABLE ACCESS FULL| T2 | 10000 | 30000 | 9 |
--------------------------------------------------------------------

Now we know it's the CBO creating this plan, as both the hinted and
un-hinted queries produce the same execution path.

All of this was run on Oracle 9.2.0.6, on Solaris 8.

I am not aware of any CBO anomalies in 9.2.0.6, and I haven't found
time nor space to install 10g. And, I'm hoping Jonathan Lewis can shed
some light on these plans. I do not know the Oracle internals that
well.


David Fitzjarrell

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  #3 (permalink)  
Old 02-24-2008, 01:49 PM
derek
 
Posts: n/a
Default Re: non equi-joins

Hi David,
Sincere apologies for duplicate posting. Thanks a lot for helping me
out!! However, there is another aspect of the execution trace which I
could not understand. I have the trace output of the same query as
earlier pasted below. When I checked the "time" values in the "Row
source operation" of the execution plan, I find that the time value of
the merge phase is much higher than the value in the sort aggregate.
Does that mean that the "merge time" is the projected time had the
merge operation been materialised instead of just being pipelined to be
aggregated? Or am I missing some thing? Hope to hear from you soon.

best regards,
Nagender.




select /*+ ORDERED USE_MERGE (f1 f2)*/count(*)
from
test2 f2, test1 f1 where f1.a = f2.a


call count cpu elapsed disk query current
rows
------- ------ -------- ---------- ---------- ---------- ----------
----------
Parse 1 0.00 0.00 0 0 0
0
Execute 1 0.00 0.00 0 0 0
0
Fetch 2 0.04 0.05 0 32 0
1
------- ------ -------- ---------- ---------- ---------- ----------
----------
total 4 0.04 0.05 0 32 0
1

Misses in library cache during parse: 0
Optimizer mode: ALL_ROWS
Parsing user id: 58

Rows Row Source Operation
------- ---------------------------------------------------
1 SORT AGGREGATE (cr=32 pr=0 pw=0 time=51752 us)
36000 MERGE JOIN (cr=32 pr=0 pw=0 time=159758 us)
3000 SORT JOIN (cr=16 pr=0 pw=0 time=15583 us)
3000 TABLE ACCESS FULL TEST2 (cr=16 pr=0 pw=0 time=3179 us)
36000 SORT JOIN (cr=16 pr=0 pw=0 time=43848 us)
3000 TABLE ACCESS FULL TEST1 (cr=16 pr=0 pw=0 time=3068 us)

************************************************** ******************************

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  #4 (permalink)  
Old 02-24-2008, 01:49 PM
Carlos
 
Posts: n/a
Default Re: non equi-joins

>> Post your question ONCE, and in properl English...

I think 'properl English' is not so 'proper'.

Cheers.

Carlos.

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  #5 (permalink)  
Old 02-24-2008, 01:50 PM
fitzjarrell@cox.net
 
Posts: n/a
Default Re: non equi-joins



Carlos wrote:
> >> Post your question ONCE, and in properl English...

>
> I think 'properl English' is not so 'proper'.
>
> Cheers.
>
> Carlos.



My typo is far better than trying to use 'wot' as a word, which was the
intent of the admonishment.

Apparently you have nothing better to do than nitpick responses. I find
NOTHING of any value to the original poster in your post.

Or, did I miss something???


David Fitzjarrell

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  #6 (permalink)  
Old 02-24-2008, 01:50 PM
fitzjarrell@cox.net
 
Posts: n/a
Default Re: non equi-joins



derek wrote:
> Hi David,
> Sincere apologies for duplicate posting. Thanks a lot for helping me
> out!! However, there is another aspect of the execution trace which I
> could not understand. I have the trace output of the same query as
> earlier pasted below. When I checked the "time" values in the "Row
> source operation" of the execution plan, I find that the time value of
> the merge phase is much higher than the value in the sort aggregate.
> Does that mean that the "merge time" is the projected time had the
> merge operation been materialised instead of just being pipelined to be
> aggregated? Or am I missing some thing? Hope to hear from you soon.
>
> best regards,
> Nagender.
>
>
>
>
> select /*+ ORDERED USE_MERGE (f1 f2)*/count(*)
> from
> test2 f2, test1 f1 where f1.a = f2.a
>
>
> call count cpu elapsed disk query current
> rows
> ------- ------ -------- ---------- ---------- ---------- ----------
> ----------
> Parse 1 0.00 0.00 0 0 0
> 0
> Execute 1 0.00 0.00 0 0 0
> 0
> Fetch 2 0.04 0.05 0 32 0
> 1
> ------- ------ -------- ---------- ---------- ---------- ----------
> ----------
> total 4 0.04 0.05 0 32 0
> 1
>
> Misses in library cache during parse: 0
> Optimizer mode: ALL_ROWS
> Parsing user id: 58
>
> Rows Row Source Operation
> ------- ---------------------------------------------------
> 1 SORT AGGREGATE (cr=32 pr=0 pw=0 time=51752 us)
> 36000 MERGE JOIN (cr=32 pr=0 pw=0 time=159758 us)
> 3000 SORT JOIN (cr=16 pr=0 pw=0 time=15583 us)
> 3000 TABLE ACCESS FULL TEST2 (cr=16 pr=0 pw=0 time=3179 us)
> 36000 SORT JOIN (cr=16 pr=0 pw=0 time=43848 us)
> 3000 TABLE ACCESS FULL TEST1 (cr=16 pr=0 pw=0 time=3068 us)
>
> ************************************************** ******************************


This is tkprof output, generated from a session trace, where the query
was actually executed and a result set returned, so no 'projected'
values are present. All times reported, afaik, are actual elapsed
times. Note, however, the time in the explain plan portion is in
microseconds, and the times reported by tkprof in the summary section
are in 1/100ths of a second. The MERGE JOIN consumed 159758
microseconds; this converts to roughly 160 milliseconds or 0.16 seconds
(roundng up). The CPU time for this same query was only 0.04 seconds,
so it would appear you were waiting for a resource for the merge join.
I can't say for certain as I don't have the trace file to examine, but
I wonder what value you've set for your sort_area_size. And I did
notice this is not the same query you originally posted, as you're now
using an equi-join.

Jonathan Lewis and Tom Kyte cover reading and interpreting this output
in their texts. Also, since you're concerned with what the optimiser
is actually doing, you might want to set event 10053 at level 1 for a
dump of the optimiser calculations/operations for this same query.
Between the two trace files you should be able to interpret what Oracle
is doing with your query, and, hopefully, why it's choosing the
operations it's reporting.


David Fitzjarrell

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  #7 (permalink)  
Old 02-24-2008, 01:53 PM
Jonathan Lewis
 
Posts: n/a
Default Re: non equi-joins



The system hasn't sorted multiple times.

Your assumption about how the mechanism
ought to work is correct, and does describe
what happens. You can check this by looking
at you session stats, or doing an autotrace.

You will find that you have done 2 sorts, and
sorted 20,000 rows.

For your example, Oracle sorts both inputs,
and writes the second output to 'TEMP'. Then
for each row in the first output it will find a start
and end point in the second output and join.

The 49995000 beside the second sort line:
> 49995000 SORT JOIN (cr=38 pr=0 pw=0 time=50031081 us)

is the number of rows supplied as a result
of that sorted row source - but Oracle
has only sorted it once, than kept
're-supplying' the required results.

Ideally there ought to be a line which is
the parent of the sort operation that is
an 'ordered selection output' line (or
something similar) so that you could
see that the sort generated 10,000 rows,
and then it's output was scanned in order
many times.



--
Regards

Jonathan Lewis

http://www.jlcomp.demon.co.uk/faq/ind_faq.html
The Co-operative Oracle Users' FAQ

http://www.jlcomp.demon.co.uk/seminar.html
Public Appearances - schedule updated April 5th 2005






<dereksmi@gmail.com> wrote in message
news:1117586398.259896.157200@g14g2000cwa.googlegr oups.com...
>
>
> Hi,
>
> I have two tables t1 and t2 containing 10K tuples each. I tried to do a
> non equi-join on these tables using the following query.
>
> select /*+ ORDERED USE_MERGE (t2 t1)*/count(*) from test2 t2, test1 t1
> where t2.a > t1.a;
>
> A simple implementaion of Sort merge based non equi join would have
> sorted both relations and iterated through the outer relation returning
> all the matching tuples. However when I checked the execution plan made
> by Oracle. this is wot it shows
>
>
> Rows Row Source Operation
> ------- ---------------------------------------------------
> 1 SORT AGGREGATE (cr=76 pr=0 pw=0 time=26809424 us)
> 49995000 MERGE JOIN (cr=76 pr=0 pw=0 time=150014986 us)
> 10000 SORT JOIN (cr=38 pr=0 pw=0 time=26064 us)
> 10000 TABLE ACCESS FULL TEST2 (cr=38 pr=0 pw=0 time=10086 us)
> 49995000 SORT JOIN (cr=38 pr=0 pw=0 time=50031081 us)
> 10000 TABLE ACCESS FULL TEST1 (cr=38 pr=0 pw=0 time=10055 us)
>
>
> Why does it sort the inner relation multiple times? Is there a way to
> avoid it? Any help would be greatly appreciated!!
>
> best regards,
> Derek.
>



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