Unix Technical Forum

SEO

vBulletin Search Engine Optimization


Go Back   Unix Technical Forum > Database Server Software > Microsoft SQL Server > SQL Server

Register FAQ Members List Calendar Search Today's Posts Mark Forums Read
  #1 (permalink)  
Old 02-28-2008, 07:07 PM
Fred Thompson
 
Posts: n/a
Default Need help with MS SQL query

I'm using MS SQL 2000 server. I have a table which includes a date field
which has people's birthdays in it. How can I write a query to return all
the records of people with birthdays within the next 30 days? (Based on
system date as the starting point.) Actual year of birthday is irrelevant.
Also the next 30 days may span into the next month, or the next year.


Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #2 (permalink)  
Old 02-28-2008, 07:07 PM
Greg D. Moore \(Strider\)
 
Posts: n/a
Default Re: Need help with MS SQL query


"Fred Thompson" <fredr@aol.com> wrote in message
newsISAb.456981$HS4.3574769@attbi_s01...
> I'm using MS SQL 2000 server. I have a table which includes a date field
> which has people's birthdays in it. How can I write a query to return all
> the records of people with birthdays within the next 30 days? (Based on
> system date as the starting point.) Actual year of birthday is

irrelevant.
> Also the next 30 days may span into the next month, or the next year.
>


Something like

select lname, birthdate from birthtable where birthdate> getdate() and
birthdate< getdate()+30


>



Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #3 (permalink)  
Old 02-28-2008, 07:07 PM
Fred Thompson
 
Posts: n/a
Default Re: Need help with MS SQL query

But this takes year into account, so your query will only select people born
30 days into the future.
I need the query to select anyone whose birthday is coming up in the next 30
days regardless of what year they were born.

"Greg D. Moore (Strider)" <mooregr@greenms.com> wrote in message
news:OPTAb.191750$1N3.128360@twister.nyroc.rr.com. ..
>
> "Fred Thompson" <fredr@aol.com> wrote in message
> newsISAb.456981$HS4.3574769@attbi_s01...
> > I'm using MS SQL 2000 server. I have a table which includes a date

field
> > which has people's birthdays in it. How can I write a query to return

all
> > the records of people with birthdays within the next 30 days? (Based on
> > system date as the starting point.) Actual year of birthday is

> irrelevant.
> > Also the next 30 days may span into the next month, or the next year.
> >

>
> Something like
>
> select lname, birthdate from birthtable where birthdate> getdate() and
> birthdate< getdate()+30
>
>
> >

>
>



Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #4 (permalink)  
Old 02-28-2008, 07:07 PM
John Gilson
 
Posts: n/a
Default Re: Need help with MS SQL query

"Fred Thompson" <fredr@aol.com> wrote in message newsISAb.456981$HS4.3574769@attbi_s01...
> I'm using MS SQL 2000 server. I have a table which includes a date field
> which has people's birthdays in it. How can I write a query to return all
> the records of people with birthdays within the next 30 days? (Based on
> system date as the starting point.) Actual year of birthday is irrelevant.
> Also the next 30 days may span into the next month, or the next year.


Here's a UDF that will find all birthdays N days from a given reference date.
For your case, N = 30 and the reference date = today.

CREATE TABLE Birthdays
(
person_name VARCHAR(25) NOT NULL PRIMARY KEY,
birthday DATETIME NOT NULL CHECK (birthday <= CURRENT_TIMESTAMP)
)

CREATE VIEW Today (d)
AS
SELECT CAST(CONVERT(CHAR(8), CURRENT_TIMESTAMP, 112) AS
DATETIME)

-- Returns all persons whose birthday is within @ndays of @ref_date
-- Assumes @ref_date has a time of 12AM
-- Default @ref_date is today
CREATE FUNCTION BirthdaysNDaysFromDate
(@ndays INT, @ref_date DATETIME = NULL)
RETURNS TABLE
AS
RETURN(
SELECT person_name,
birthday,
COALESCE(@ref_date, (SELECT d FROM Today)) AS reference_date
FROM Birthdays
WHERE birthday <=
COALESCE(@ref_date, (SELECT d FROM Today)) + @ndays AND
(YEAR(COALESCE(@ref_date, (SELECT d FROM Today))) <
YEAR(COALESCE(@ref_date, (SELECT d FROM Today)) + @ndays) OR
(DATEADD(YEAR,
YEAR(COALESCE(@ref_date, (SELECT d FROM Today))) -
YEAR(birthday),
birthday) BETWEEN
COALESCE(@ref_date, (SELECT d FROM Today)) AND
COALESCE(@ref_date, (SELECT d FROM Today)) + @ndays)) AND
(YEAR(COALESCE(@ref_date, (SELECT d FROM Today))) =
YEAR(COALESCE(@ref_date, (SELECT d FROM Today)) + @ndays) OR
DATEADD(YEAR,
YEAR(COALESCE(@ref_date,
(SELECT d FROM Today))) - YEAR(birthday),
birthday) >=
COALESCE(@ref_date, (SELECT d FROM Today)) OR
DATEADD(YEAR,
YEAR(COALESCE(@ref_date, (SELECT d FROM Today)) +
@ndays) - YEAR(birthday),
birthday) <=
COALESCE(@ref_date, (SELECT d FROM Today)) + @ndays)
)

-- Uses today as the reference date
CREATE FUNCTION BirthdaysNDaysFromToday (@ndays INT)
RETURNS TABLE
AS
RETURN(
SELECT *
FROM BirthdaysNDaysFromDate(@ndays, DEFAULT)
)

INSERT INTO Birthdays (person_name, birthday)
VALUES ('Joe', '19801231')
INSERT INTO Birthdays (person_name, birthday)
VALUES ('Jim', '20000101')
INSERT INTO Birthdays (person_name, birthday)
VALUES ('Jerry', '19500610')

-- All birthdays 30 days from today, 20031208
SELECT *
FROM BirthdaysNDaysFromToday(30)

person_name birthday reference_date
Jim 2000-01-01 00:00:00.000 2003-12-08 00:00:00.000
Joe 1980-12-31 00:00:00.000 2003-12-08 00:00:00.000

-- All birthdays 180 days from 19811215
-- Given this reference date, Jim wasn't born yet
SELECT *
FROM BirthdaysNDaysFromDate(180, '19811215')

person_name birthday reference_date
Jerry 1950-06-10 00:00:00.000 1981-12-15 00:00:00.000
Joe 1980-12-31 00:00:00.000 1981-12-15 00:00:00.000

Regards,
jag


Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #5 (permalink)  
Old 02-28-2008, 07:07 PM
Ronnie Chee
 
Posts: n/a
Default Re: Need help with MS SQL query

"Fred Thompson" <fredr@aol.com> wrote in message
newsISAb.456981$HS4.3574769@attbi_s01...
> I'm using MS SQL 2000 server. I have a table which includes a date field
> which has people's birthdays in it. How can I write a query to return all
> the records of people with birthdays within the next 30 days? (Based on
> system date as the starting point.) Actual year of birthday is

irrelevant.
> Also the next 30 days may span into the next month, or the next year.
>
>

Here is a half-baked idea (totally untested as well):

select lname, birthdate
from birthdaytable
where datediff(year, birthdate, getdate()) < datediff(year, birthdate,
dateadd(day,30, getdate()))

Assuming datediff(year, ...) rounds down.
I think that this will be a poor performer in that it should force a table
scan but depending on how large the birthday table is, this may be
irrelevant.

Hope this helps
Ronnie


Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #6 (permalink)  
Old 02-28-2008, 07:08 PM
louis nguyen
 
Posts: n/a
Default Re: Need help with MS SQL query

"Fred Thompson" <fredr@aol.com> wrote in message news:<DISAb.456981$HS4.3574769@attbi_s01>...
> I'm using MS SQL 2000 server. I have a table which includes a date field
> which has people's birthdays in it. How can I write a query to return all
> the records of people with birthdays within the next 30 days? (Based on
> system date as the starting point.) Actual year of birthday is irrelevant.
> Also the next 30 days may span into the next month, or the next year.

Hi Fred,

The simplest way I can think of is create a temp table with the next
30 days and join it against your birthday table on month()=month() and
day()=day(). The code would be like:

create table #T(bdays datetime)
declare @i int, @d datetime
select @d=getdate()
select @d=cast(year(@d) as varchar)
+'/'+cast(month(@d) as varchar)
+'/'+cast(day(@d) as varchar)

set @i=0
while @i<=30 begin
insert into #T
select bdays=dateadd(day,@i,@d)
set @i=@i+1
end

select a.bdays
from birthdays as a
join #T as b
on month(a.bdays)=month(b.bdays)
and day(a.bdays)=day(b.bdays)
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #7 (permalink)  
Old 02-28-2008, 07:08 PM
Igor Raytsin
 
Posts: n/a
Default Re: Need help with MS SQL query

I didn't test it, but you'll get the idea:

SELECT Name, birthday, DATEDIFF(yy, birthday, getdate()) as years_now,
DATEDIFF(yy, birthday, (getdate() +30) ) as years_will_be
FROM table
WHERE DATEDIFF(yy, birthday, getdate()) < DATEDIFF(yy, birthday, (getdate()
+30) )


-----
Hope this helps


"Fred Thompson" <fredr@aol.com> wrote in message
newsISAb.456981$HS4.3574769@attbi_s01...
> I'm using MS SQL 2000 server. I have a table which includes a date field
> which has people's birthdays in it. How can I write a query to return all
> the records of people with birthdays within the next 30 days? (Based on
> system date as the starting point.) Actual year of birthday is

irrelevant.
> Also the next 30 days may span into the next month, or the next year.
>
>



Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #8 (permalink)  
Old 02-29-2008, 05:44 AM
tony_petruzzi@sheriff.org
 
Posts: n/a
Default Re: Need help with MS SQL query

select *
from table
where datediff(day, getdate(), dateadd(year, (year(getdate()) -
year(birthday)), birthday)) < 30

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump


All times are GMT. The time now is 08:49 PM.


Powered by vBulletin® Version 3.6.5
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0
UnixAdminTalk.com

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 452 453 454 455 456 457 458 459 460 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596 597 598 599 600 601 602 603 604 605 606 607 608 609 610 611 612 613 614 615 616 617 618 619 620 621 622 623 624 625 626 627 628 629 630 631 632 633 634 635 636 637 638 639 640 641 642 643 644 645 646 647 648 649 650 651 652 653 654 655 656 657 658 659 660 661 662 663 664 665 666 667 668 669 670 671 672 673 674 675 676 677 678 679 680 681 682 683 684 685 686 687 688 689 690 691 692 693 694 695 696 697 698 699 700 701 702 703 704 705 706 707 708 709 710 711 712 713 714 715 716 717 718 719 720 721 722 723 724 725 726 727 728 729 730 731 732 733 734 735 736 737 738 739 740 741 742 743 744 745 746 747 748 749 750 751 752 753 754 755 756 757 758 759 760 761 762 763 764 765 766 767 768 769 770 771 772 773 774 775 776 777 778 779 780 781 782 783 784 785 786 787 788 789 790 791 792 793 794 795 796 797 798 799 800 801 802 803 804 805 806 807 808 809 810 811 812