Unix Technical Forum

SEO

vBulletin Search Engine Optimization


Go Back   Unix Technical Forum > Database Server Software > Microsoft SQL Server > SQL Server

Register FAQ Members List Calendar Search Today's Posts Mark Forums Read
  #1 (permalink)  
Old 03-01-2008, 11:54 AM
ice
 
Posts: n/a
Default Selecting last date

Hello,
I have a couple of tables. The client tables and the contacted
tables.
I am not sure how to start on this, what I need is a way to query all
my clients
then show any client that the last visit and or called day is greater
than 30 days.
Now it gets confusing, Suppose the client was visited more than 30 days
ago
but was called only 10 days ago, I really would like to have this
appear on the same
query.
So the report would look similar to this below.
Visit Date Called Date
ClientA 2006-11-02 2006-12-16
ClientB 2006-12-17 2006-10-30
ClientC 2006-10-15 2006-10-16
ClientD

Fields (Simplified)
Clients: Name, Address, Phone.
Contacted: Name, Date, Visit, Call.
I need to query all l names, but I only need the last visit and last
phone call. Then determine if either date is greater than 30 days if
so, display the last date of each type of contact. And if there is
nothing for the client in the contacted table this needs to show also,
ClientD.
Any tips, ideas would be greatly appreciated....
Thanks
Ice

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #2 (permalink)  
Old 03-01-2008, 11:54 AM
Erland Sommarskog
 
Posts: n/a
Default Re: Selecting last date

ice (iceruam@gmail.com) writes:
> I have a couple of tables. The client tables and the contacted
> tables.
> I am not sure how to start on this, what I need is a way to query all
> my clients then show any client that the last visit and or called day
> is greater than 30 days.
> Now it gets confusing, Suppose the client was visited more than 30 days
> ago but was called only 10 days ago, I really would like to have this
> appear on the same query.
>
> So the report would look similar to this below.
> Visit Date Called Date
> ClientA 2006-11-02 2006-12-16
> ClientB 2006-12-17 2006-10-30
> ClientC 2006-10-15 2006-10-16
> ClientD
>
> Fields (Simplified)
> Clients: Name, Address, Phone.
> Contacted: Name, Date, Visit, Call.
> I need to query all l names, but I only need the last visit and last
> phone call. Then determine if either date is greater than 30 days if
> so, display the last date of each type of contact. And if there is
> nothing for the client in the contacted table this needs to show also,
> ClientD.


It's a good recommendation for this type of queries to post CREATE
TABLE statements for your tables, and INSERT statements with sample
data, and the desired output given the sample. That makes it easy to
copy and paste to develop a tested solution. The sample data can also
help to clarify the narrative. The below is thus untested and based
on my understanding of your description.

SELECT Cl.Name, V.Date, C.Date
FROM Clients Cl
LEFT JOIN (SELECT Name, Date = MAX(Date)
FROM Contacted
WHERE Visit = 1
GROUP BY Contaced) AS V ON V.Name = Cl.Name
LEFT JOIN (SELECT Name, Date = MAX(Date)
FROM Contacted
WHERE Call = 1
GROUP BY Contaced) AS C ON C.Name = Cl.Name
WHERE V.Date < datedadd(day, -30, getdate()) OR V.Date IS NULL

The things in parens are derived tables. Conceptually a temp table
in the query, but not materialised, and SQL Server may recast computation
order, as long as the result is the same. This makes derived tables a
very powerful features to implement complex queries.


--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #3 (permalink)  
Old 03-01-2008, 11:55 AM
ice
 
Posts: n/a
Default Re: Selecting last date


Erland Sommarskog wrote:
> ice (iceruam@gmail.com) writes:
> > I have a couple of tables. The client tables and the contacted
> > tables.
> > I am not sure how to start on this, what I need is a way to query all
> > my clients then show any client that the last visit and or called day
> > is greater than 30 days.
> > Now it gets confusing, Suppose the client was visited more than 30 days
> > ago but was called only 10 days ago, I really would like to have this
> > appear on the same query.
> >
> > So the report would look similar to this below.
> > Visit Date Called Date
> > ClientA 2006-11-02 2006-12-16
> > ClientB 2006-12-17 2006-10-30
> > ClientC 2006-10-15 2006-10-16
> > ClientD
> >
> > Fields (Simplified)
> > Clients: Name, Address, Phone.
> > Contacted: Name, Date, Visit, Call.
> > I need to query all l names, but I only need the last visit and last
> > phone call. Then determine if either date is greater than 30 days if
> > so, display the last date of each type of contact. And if there is
> > nothing for the client in the contacted table this needs to show also,
> > ClientD.

>
> It's a good recommendation for this type of queries to post CREATE
> TABLE statements for your tables, and INSERT statements with sample
> data, and the desired output given the sample. That makes it easy to
> copy and paste to develop a tested solution. The sample data can also
> help to clarify the narrative. The below is thus untested and based
> on my understanding of your description.
>
> SELECT Cl.Name, V.Date, C.Date
> FROM Clients Cl
> LEFT JOIN (SELECT Name, Date = MAX(Date)
> FROM Contacted
> WHERE Visit = 1
> GROUP BY Contaced) AS V ON V.Name = Cl.Name
> LEFT JOIN (SELECT Name, Date = MAX(Date)
> FROM Contacted
> WHERE Call = 1
> GROUP BY Contaced) AS C ON C.Name = Cl.Name
> WHERE V.Date < datedadd(day, -30, getdate()) OR V.Date IS NULL
>
> The things in parens are derived tables. Conceptually a temp table
> in the query, but not materialised, and SQL Server may recast computation
> order, as long as the result is the same. This makes derived tables a
> very powerful features to implement complex queries.
>
>
> --
> Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se
>
> Books Online for SQL Server 2005 at
> http://www.microsoft.com/technet/pro...ads/books.mspx
> Books Online for SQL Server 2000 at
> http://www.microsoft.com/sql/prodinf...ons/books.mspx



THANKS, I will give this a go.
ICE

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #4 (permalink)  
Old 03-01-2008, 11:55 AM
ice
 
Posts: n/a
Default Re: Selecting last date


Erland Sommarskog wrote:
> ice (iceruam@gmail.com) writes:
> > I have a couple of tables. The client tables and the contacted
> > tables.
> > I am not sure how to start on this, what I need is a way to query all
> > my clients then show any client that the last visit and or called day
> > is greater than 30 days.
> > Now it gets confusing, Suppose the client was visited more than 30 days
> > ago but was called only 10 days ago, I really would like to have this
> > appear on the same query.
> >
> > So the report would look similar to this below.
> > Visit Date Called Date
> > ClientA 2006-11-02 2006-12-16
> > ClientB 2006-12-17 2006-10-30
> > ClientC 2006-10-15 2006-10-16
> > ClientD
> >
> > Fields (Simplified)
> > Clients: Name, Address, Phone.
> > Contacted: Name, Date, Visit, Call.
> > I need to query all l names, but I only need the last visit and last
> > phone call. Then determine if either date is greater than 30 days if
> > so, display the last date of each type of contact. And if there is
> > nothing for the client in the contacted table this needs to show also,
> > ClientD.

>
> It's a good recommendation for this type of queries to post CREATE
> TABLE statements for your tables, and INSERT statements with sample
> data, and the desired output given the sample. That makes it easy to
> copy and paste to develop a tested solution. The sample data can also
> help to clarify the narrative. The below is thus untested and based
> on my understanding of your description.
>
> SELECT Cl.Name, V.Date, C.Date
> FROM Clients Cl
> LEFT JOIN (SELECT Name, Date = MAX(Date)
> FROM Contacted
> WHERE Visit = 1
> GROUP BY Contaced) AS V ON V.Name = Cl.Name
> LEFT JOIN (SELECT Name, Date = MAX(Date)
> FROM Contacted
> WHERE Call = 1
> GROUP BY Contaced) AS C ON C.Name = Cl.Name
> WHERE V.Date < datedadd(day, -30, getdate()) OR V.Date IS NULL
>
> The things in parens are derived tables. Conceptually a temp table
> in the query, but not materialised, and SQL Server may recast computation
> order, as long as the result is the same. This makes derived tables a
> very powerful features to implement complex queries.
>
>
> --
> Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se
>
> Books Online for SQL Server 2005 at
> http://www.microsoft.com/technet/pro...ads/books.mspx
> Books Online for SQL Server 2000 at
> http://www.microsoft.com/sql/prodinf...ons/books.mspx



I was not able to make it work, getting an a error about a relation.*


CREATE TABLE contacted (
"key" serial NOT NULL,
"Date" date NOT NULL,
"Phone" boolean DEFAULT false NOT NULL,
"Visit" boolean DEFAULT false NOT NULL,
"Reason" character varying(255),
"Results" character varying(255),
"Comments" character varying(255),
id integer NOT NULL,
"Enumber" integer NOT NULL,
fup boolean DEFAULT true NOT NULL,
fupdate date
);

CREATE TABLE clients (
lname character varying(30),
fname character varying(30),
company character varying(40),
address1 character varying(30),
address2 character varying(30),
city character varying(30),
state character(2),
zip character(10),
active boolean DEFAULT true,
id integer DEFAULT nextval('id_seq'::regclass) NOT NULL
);

COPY clients (lname, fname, company, address1, address2, city, state,
zip, active, id) FROM stdin;
Smith Joe Small Co Smallville Rd Bigton NY 12234 t 1
Doe Jane Dust Grabber Inc 10 Dirt Drive Dustin PA 12345-1222 t 2
Smacher Frank Woodwerkers Inc 100 Forest
Lane Oakland CA 12346-2222 t 3
Zimbob Roger Drywallz Inc 1 Gympsum Place Quarryville NY 12347
t 4
Deckem Will Porches are us 2 Backyard Lane Gazeboton CO 12348 t 5
Crimp Greg Kidocker 2 Tenfly Rd Metropolis NY 10002 t 6
\.


--

COPY contacted ("key", "Date", "Phone", "Visit", "Reason", "Results",
"Comments", id, "Enumber", fup, fupdate) FROM stdin;
1 2006-11-01 t f Promote new filters Would like a sample Sounds very
interested 2 602 t 2006-11-15
2 2006-11-01 t f Promote new filter Send Sample Sounds very
interested 3 602 t 2006-11-15
3 2006-11-02 f t Demo new air purifier Glitch in servo motor, would not
rotate the exhaust fan. Smoke coming from inside. Demo bombed, due to a
faulty oscilator motor. \nThey will call us.\nDiscussed with
engineers. 4 602 f \N
4 2006-11-03 t f Setup appointment Setup appointment for
11/28/2006 need to remind the day before 5 603 t 2008-11-27
5 2006-11-03 f t Demo Puro-203 Demo went flawless. William seemed to
be very impressed Left several pamphlets on other models for home and
business. 6 605 t 2006-11-17
6 2006-12-10 t f Just to see if they would like to have 30 day eval of
the Puro-206d Seemed interested they needed to talk with their
facilities manager Need this sale after last
disaster 4 605 t 2006-12-15
7 2006-12-15 t f Follow up Have appointment to install 2 30 day evals
of the Puro-206d 12/20/2006 Need to appease 4 605 t 2006-12-20
\.

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #5 (permalink)  
Old 03-01-2008, 11:55 AM
Erland Sommarskog
 
Posts: n/a
Default Re: Selecting last date

ice (iceruam@gmail.com) writes:
> I was not able to make it work, getting an a error about a relation.*


Seeing your tables and your COPY commands, it's apparent to me that
whatever you are using, it is not Microsoft SQL Server. The solution
I posted is almost ANSI-compliant. The exception is the expression:

datedadd(day, -30, getdate())

In ANSI SQL, getdate() should be CURRENT_TIMESTAMP. Whether dateadd (my
query mistakely had "datedadd" I see now) is in ANSI SQL, I don't know,
nor do I know about date aritmethics in general in ANSI SQL.

Thus, theoretically, beside this expression, the solution should work
if your DB engine implements the same ANSI constructs as SQL Server does.

Alas, just because a query is ANSI-compliant, does not mean that it
will run all engines, so you may have to use a solution that uses
syntax peculiar to the product that you work with. If you need help
with that, you will have to find a forum for your product. If that
product is mysql, there is a comp.databases.mysql nextdoors from here.



--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #6 (permalink)  
Old 03-01-2008, 11:55 AM
Hugo Kornelis
 
Posts: n/a
Default Re: Selecting last date

On 27 Dec 2006 11:01:28 -0800, ice wrote:

(snip)
>I was not able to make it work, getting an a error about a relation.*
>
>
>CREATE TABLE contacted (

(snip)
>COPY clients (lname, fname, company, address1, address2, city, state,
>zip, active, id) FROM stdin;
>Smith Joe Small Co Smallville Rd Bigton NY 12234 t 1

(snip)

Hi ice,

Thanks for posting the table structures. The first thing I noticed is
that some of the datatypes used are not valid on MS SQL Server. You are
apparently using some other DBMS. You might get better help when posting
in a newsgroup for your DBMS!

That being said, I am willing to look into your problem - but only if
you can post the data as INSERT statements (the COPY statement you used
is not supported on MS SQL Server either), *and* if you post the exact
and complete error message you got (use copy and paste if possible).

--
Hugo Kornelis, SQL Server MVP
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #7 (permalink)  
Old 03-01-2008, 11:55 AM
ice
 
Posts: n/a
Default Re: Selecting last date


Hugo Kornelis wrote:
> On 27 Dec 2006 11:01:28 -0800, ice wrote:
>
> (snip)
> >I was not able to make it work, getting an a error about a relation.*
> >
> >
> >CREATE TABLE contacted (

> (snip)
> >COPY clients (lname, fname, company, address1, address2, city, state,
> >zip, active, id) FROM stdin;
> >Smith Joe Small Co Smallville Rd Bigton NY 12234 t 1

> (snip)
>
> Hi ice,
>
> Thanks for posting the table structures. The first thing I noticed is
> that some of the datatypes used are not valid on MS SQL Server. You are
> apparently using some other DBMS. You might get better help when posting
> in a newsgroup for your DBMS!
>
> That being said, I am willing to look into your problem - but only if
> you can post the data as INSERT statements (the COPY statement you used
> is not supported on MS SQL Server either), *and* if you post the exact
> and complete error message you got (use copy and paste if possible).
>
> --
> Hugo Kornelis, SQL Server MVP

OK.
Thanks.

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #8 (permalink)  
Old 03-01-2008, 11:57 AM
--CELKO--
 
Posts: n/a
Default Re: Selecting last date

>> In ANSI SQL, getdate() should be CURRENT_TIMESTAMP. Whether dateadd (my query mistakely had "datedadd" I see now) is in ANSI SQL, I don't know, nor do I know about date aritmethics in general in ANSI SQL. <<

It is not ANSI/ISO. Temporal math in Standard has infixed operators +
and - with temporal unit declarations, EXTRACT() and oher functions
that are very different from the Sybase/SQL Server "code museum"
function calls. DB2 and Oracle 10 now both have the proper syntax. I
thnk that Mimer and Solid are also up to standards.

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #9 (permalink)  
Old 03-01-2008, 11:57 AM
Erland Sommarskog
 
Posts: n/a
Default Re: Selecting last date

--CELKO-- (jcelko212@earthlink.net) writes:
>>> In ANSI SQL, getdate() should be CURRENT_TIMESTAMP. Whether dateadd (my

query mistakely had "datedadd" I see now) is in ANSI SQL, I don't know, nor
do I know about date aritmethics in general in ANSI SQL. <<
>
> It is not ANSI/ISO. Temporal math in Standard has infixed operators +
> and - with temporal unit declarations, EXTRACT() and oher functions
> that are very different from the Sybase/SQL Server "code museum"
> function calls. DB2 and Oracle 10 now both have the proper syntax. I
> thnk that Mimer and Solid are also up to standards.


SQL Server also has +/- for datetime, although I suspect this is due
to implicit conversion. Look at this:

declare @d1 datetime, @d2 datetime
select @d1 = '19820223 16:21:32', @d2 = '19871031 12:23:23'
select @d1 + 1, @d2 - @d1

Gives:

1982-02-24 16:21:32.000 1905-09-07 20:01:51.000

The first makes perfect sense, the second is just rubbish.

The dateadd() etc stuff is not that pretty, but the get the job done.


--
Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #10 (permalink)  
Old 03-01-2008, 11:57 AM
--CELKO--
 
Posts: n/a
Default Re: Selecting last date

>> SQL Server also has +/- for datetime, although I suspect this is due to implicit conversion. <<

The ANSI/ISO version has to have temporal units with the +/- like
this:

(my_date + INTERVAL 2 DAYS)

This makes more sense and avoids the rubbish.

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump


All times are GMT. The time now is 08:07 AM.


Powered by vBulletin® Version 3.6.5
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0
UnixAdminTalk.com

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 452 453 454 455 456 457 458 459 460 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556