SEO

#1 (**permalink**) 04-10-2008, 12:02 AM

for example I have this:

for each product where prod-name begins "a":
display prod-name pack skip.
end.

I wanted to put in a conditional "break by" using a string like so:

def var by-name as char init "break by prod-name".

for each product where prod-name begins "a" by-name:
display prod-name pack skip.
end.

this failed.

Then I tried it with a logical like so:

def var by-name as log init no.

for each product where prod-name begins "a"
if by-name = no then break by pack
else break by prod-name:
display prod-name pack skip.
end.

This also failed. Is there a way of doing this without using a .i file?

Thanks Martin

#2 (**permalink**) 04-10-2008, 12:02 AM

Try this:

/* Using an if function rather than an if statement. */

for each product where prod-name begins "a"
break by if by-name = no then pack else prod-name:
display prod-name pack skip.
end.

<martin.doherty@gmail.com> wrote in message
news:1138103879.815153.133160@g49g2000cwa.googlegr oups.com...
> for example I have this:
>
> for each product where prod-name begins "a":
> display prod-name pack skip.
> end.
>
> I wanted to put in a conditional "break by" using a string like so:
>
> def var by-name as char init "break by prod-name".
>
> for each product where prod-name begins "a" by-name:
> display prod-name pack skip.
> end.
>
> this failed.
>
> Then I tried it with a logical like so:
>
> def var by-name as log init no.
>
> for each product where prod-name begins "a"
> if by-name = no then break by pack
> else break by prod-name:
> display prod-name pack skip.
> end.
>
> This also failed. Is there a way of doing this without using a .i file?
>
> Thanks Martin
>

#3 (**permalink**) 04-10-2008, 12:02 AM

Foley,

By God it works!

Thanks for that one,

Martin

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SEO

Substituting break by