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| Hi, Isn't this a bug about trim both. select trim(both '<BR/>' from '<BR/>ROI Engineering Inc.'); btrim --------------------- OI Engineering Inc. (1 row) "R" is missing? How? version ------------------------------------------------------------------------- PostgreSQL 8.0.15 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.3.2 Thank you! -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| Emi Lu <emilu@encs.concordia.ca> writes: > select trim(both '<BR/>' from '<BR/>ROI Engineering Inc.'); > btrim > --------------------- > OI Engineering Inc. > (1 row) > "R" is missing? How? The first argument of trim is a set, not a sequence --- it means trim any characters belonging to this set. regards, tom lane -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| On Fri, 25 Apr 2008, Emi Lu wrote: > Hi, > > Isn't this a bug about trim both. > > select trim(both '<BR/>' from '<BR/>ROI Engineering Inc.'); > btrim > --------------------- > OI Engineering Inc. > (1 row) > > > "R" is missing? How? Trim doesn't do what you think it does. The '<BR/>' in the above is not a string to remove it is a list of characters to remove. Thus, the R is removed as it matches a character given. -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| > -----Mensaje original----- > De: pgsql-sql-owner@postgresql.org > [mailto > Enviado el: Viernes, 25 de Abril de 2008 17:46 > Para: Emi Lu > CC: pgsql-sql@postgresql.org > Asunto: Re: [SQL] trim(both) problem? > > On Fri, 25 Apr 2008, Emi Lu wrote: > > > Hi, > > > > Isn't this a bug about trim both. > > > > select trim(both '<BR/>' from '<BR/>ROI Engineering Inc.'); > > btrim > > --------------------- > > OI Engineering Inc. > > (1 row) > > > > > > "R" is missing? How? > > Trim doesn't do what you think it does. The '<BR/>' in the > above is not a string to remove it is a list of characters to > remove. Thus, the R is removed as it matches a character given. > You could probably use instead: select replace('<BR/>ROI Engineering Inc.', '<BR/>', '') -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| "Fernando Hevia" <fhevia@ip-tel.com.ar> writes: >> Trim doesn't do what you think it does. The '<BR/>' in the >> above is not a string to remove it is a list of characters to >> remove. Thus, the R is removed as it matches a character given. > You could probably use instead: > select replace('<BR/>ROI Engineering Inc.', '<BR/>', '') That would zap occurrences in the middle of the string, though. regexp_replace would be better since it'd allow anchoring the pattern, eg select regexp_replace('<BR/>ROI Engineering Inc.', '^<BR/>', ''); select regexp_replace('ROI Engineering Inc.<BR/>', '<BR/>$', ''); regards, tom lane -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| --- Emi Lu <emilu@encs.concordia.ca> wrote: > Isn't this a bug about trim both. > > select trim(both '<BR/>' from '<BR/>ROI Engineering Inc.'); > btrim > --------------------- > OI Engineering Inc. > (1 row) > > > "R" is missing? How? you misread - '<BR/>' argument is a list of characters, _not_ a string. change 'ROI' to 'XOI' and you'll see. __________________________________________________ __________________________________ Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i...Dypao8Wcj9tAcJ -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |
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| Thanks a lot for all help! I understand how trim work now. >> You could probably use instead: >> select replace('<BR/>ROI Engineering Inc.', '<BR/>', '') > That would zap occurrences in the middle of the string, though. > regexp_replace would be better since it'd allow anchoring the > pattern, eg > > select regexp_replace('<BR/>ROI Engineering Inc.', '^<BR/>', ''); > select regexp_replace('ROI Engineering Inc.<BR/>', '<BR/>$', ''); This is exactly I am looking for, but my version PostgreSQL 8.0.15 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.3.2 does not support this func, and have to think about the other way to 'trim' the ^<BR/> & <BR>$ Thank you again! -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql |